Physics, 08.10.2019 06:30 josephrosanne18

Instantaneous acceleration describes how fast a is changing at a specific instant.

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Answer from: reycaden

It is the limit of acceleration for any given point within the displacement vector. Instantaneous acceleration is how fast a velocity is changing at a specific instant.

Answer from: denysmayatskyy

Answer;

Velocity

Explanation;

Instantaneous acceleration is how fast a velocity is changing at a specific instant.

Acceleration is the change in an object's velocity divided by time.Instantaneous acceleration is the acceleration of an object at a specific moment of time or instant. instantaneous acceleration is the instantaneous change of velocity over an instance of time.It is given by the formula; a = dv/dt; where dv is the derivative of v , and dt is the derivative of t.

Answer from: Quest

are you like autistic or something?

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

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