How much heat must be removed to freeze a tray of ice cubes if the water has a mass of 40.0 g? (the molar heat of fusion of water is 6.01 kj/mol.)

We sill use the formula:
Q = nl, where Q is the heat, n is the number of moles and l is the latent molar heat of fusion of water.

moles = mass / Mr
n = 40 / 18
n = 2.22 moles

Q = 2.22 x 6.01
Q = 13.34 kJ of heat must be removed

Uncle grandma

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