During takeoff, a plane goes from 0 to 50 m/s in 8s. what is its acceleration? halos fast is it going after 5 s? how far had it traveled by the time it reaches 50 m/s?

Answer : Its acceleration is,

The velocity after 5 s is, 31.25 m/s

The distance traveled by the time it reaches 50 m/s is, 200 m

Solution :

First we have to calculate the acceleration.

Formula used :

where,

a = acceleration

v = change in velocity = 50 - 0 = 50 m/s

t = time = 8 s

Now put all he given values in the above formula, we get

Therefore, its acceleration is,

Now we have to calculate the velocity after 5 second.

Formula used :

where,

v = final velocity

u = initial velocity = 0 m/s

a = acceleration =

t = time = 5 s

Now put all the given values in the above formula, we get

Therefore, the velocity after 5 s is, 31.25 m/s

Now we have to calculate the distance traveled by the time it reaches 50 m/s.

Formula used :

where,

s = distance traveled

Now put all the given values in the above formula, we get

Therefore, the distance traveled by the time it reaches 50 m/s is, 200 m

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia