A75 kg box slides down a 25.0 degree ramp with an acceleration of 3.60 m/s^2.
find coefficient between the box and the ramp. what acceleration would a 175 kg box have on this ramp?

The coefficient and acceleration are 0.061 and 8.284 m/s².

Explanation:

Given that,

Mass = 75 kg

Angle = 25.0°

Acceleration = 3.60 m/s²

We need to find the force

Now, we need to calculate the parallel force

We calculate the friction force

If the box is moving in an angle, then the weight

If it is horizontally then

So, The normal force is

We need to calculate the coefficient between the box and ramp

Where, =friction coefficient

=frictional force

F''=normal force

Put the value into the formula

We need to calculate the acceleration

Hence, The coefficient and acceleration are 0.061 and 8.284 m/s².

it takes about 30 days for it to break down

unbalanced force

explanation: