An "e" tuning fork with a frequency of 329 hz is used to test the "e" note of a piano. four beats are heard. this means

the piano key is in tune.
the piano key is out of tune and has a frequency of 333 hz.
the piano key is out of tune and has a frequency of 325 hz.
the piano key is out of tune and has a frequency of either 325 or 333 hz

The correct choice is

The piano key is out of tune and has a frequency of either 325 or 333 Hz

Beat frequency has been given as 4 Hz. hence the frequency must be above or below the given frequency of 329 Hz by 4 Hz. To get the upper level of frequency we add the beat frequency to the given frequency. To get the lower level, we subtract the beat frequency from the given frequency

f' = 329 + 4 = 333 Hz

and

f'' = 329 - 4 = 325 Hz

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.