A50.-newton horizontal force is needed to keep an object weighing 500. newtons moving at a constant velocity of 2.0 meters per second across a horizontal surface. the magnitude of the frictional force acting on the object is

The magnitude of the frictional force acting on the object is 50 N.

Given :

Horizontal Force = 50 N

Object weight = 500 N

Constant Velocity = 2 m/sec

Solution --

Constant velocity means acceleration is zero. And from Newton's second law of motion,

 ---- (1)

Here a = 0, therefore from equation (1) we get:

where is friction force,

The magnitude of the frictional force acting on the object is 50 N.

For more information, refer the link given below

link

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this