Calculate the force between two touching grape fruits each with a radius of 0.08 meters and a mass of 0.45 kilograms

Newton's formula for the force of gravity:

                     F  =  G ·  M₁ · M₂ / D²

Here's what the letters mean:

F . . . the strength of the gravitational force between two objects
G . . . the universal gravitational constant for SI units:  6.67 x 10⁻¹¹ N·m²/kg²
M₁ . . . the mass of one object
M₂ . . . the mass of the other object
D . . . the distance between the centers of the objects

If the radius of each grapefruit is 0.08 meter and their skins are touching,
then their centers are 0.16 meter apart.

The force between them is

              F  =  G ·  M₁ · M₂ / D²

                  = (6.67 x 10⁻¹¹ N·m² / kg²) · (0.45 kg) · (0.45 kg) / (0.16 m)²

                 =  (6.67 x 10⁻¹¹ · 0.45 · 0.45) / (0.0256)   N·m²·kg²/kg²·m²

                 =  (  1.35 x 10⁻¹¹)  /  (0.0256)  Newton

                 =          5.28 x 10⁻¹⁰  Newton    (rounded)

                (about  0.0000000019 ounce)

Bag of bolts weight 29.4n

Ithink the answer is fusion