Alawnmower engine running for 20 min does 4,560,000 j of work. what is the power output of the engine? (power: p = w/t)

3800 w
228,000 w
91,200,000 w
547,200,000 w

The correct answer to the question is 3800 watt. i.e the power of the engine is 3800 watt .

CALCULATION:

As per the question, the running time of the engine t = 20 min.

We know that 1 minute = 60 seconds.

Hence, 20 min = 20 × 60 seconds

                        = 1200 seconds.

The work done by the engine W = 4,560,000 J.

We are asked to calculate the power of the engine.

The power of the engine is defined as the work done by the engine per unit time.

Mathematically power P =

                                         =

                                         =

                                         = 3800 W                   [ANS]

Here, watt (W) is the unit of power and 1 watt =  

Hence, the power of the engine is 3800 watt.

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft