Apitcher throws a softball toward the home plate. when the ball hits the catchers mitt its horizontal velocity is 32 meters/second. the softballs velocity goes to 0 meters/second in 0.5 seconds when caught. if the softball has a mass of 0.2 kilograms, whats the force of the impact?

F = (mass)(acceleration) = ma

m = 0.2 kg

Vi = 32 m/s

t = 0.5 s

Vf = 0 m/s (since it was put to stop)

a=(Vf-Vi)/t

a=(0-32)/0.5

a = 64 m/s^2 (decelerating)

F = ma = (0.2 kg)(64 m/s^2)

F = 12.8 N

Hope this answer will be a good help for you.

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