Consider a system that consists of two carts on a frictionless track and an ideal spring which is held compressed between them. The carts each have a mass of 0.5 kg and the track is supported on a table 1 m above the ground. The spring constant of the spring is 200N / m and it has been compressed 10 cm from its equilibrium length when the carts were pushed together . Which of the following indicates how much potential energy the system has? ( Note: useg=10 m/s^ 2 ) .

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.