Two loudspeakers placed 6.0 m apart are driven in phase by an audio oscillator whose frequency range is 2193 Hz to 2967 Hz. A point P is located 4.4 m from one loudspeaker and 3.6 m from the other. The speed of sound is 344 m/s. The frequency produced by the oscillator, for which constructive interference of sound occurs at point P, is closest to

"2580 Hz" is the correct solution.

Explanation:

According to the question,

The path difference,

=

=

Speed,

= 344 m/s

For constructive interference,

⇒  

On substituting the values, we get

⇒  

⇒  

⇒                

If the frequency range is,

f = 2193,

⇒  

If the frequency range is,

f = 2967,

⇒  

hence,

For n = 6, the frequency will be:

⇒  

as technology advances, new experiments often expose problems in accepted theories. c

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