At a certain point in space, an electric field of 40,000 N/C exists and it is pointed to the left. If you were to place an object with a charge of +2.0 microCoulombs at that location, what would happen to the charged object?

The answer is 4f======since electrostatic force is given by    we let f be the electrostatic force when  r = 1 m    if we let  denote the electrostatic force when the distance is decreased so that r = 0.5m, then    we established earlier that f = kq₁q₂. therefore    the force will now be 4f.