Three identical very dense masses of 3800 kg each are placed on the x axis. One mass is at x1 = - 230 cm, one is at the origin, and one is at
x2 = 350 cm. Take the gravitational constant to be G = 6.67×10−11N⋅m2
/kg2
a) calculate the gravitational attraction of the object located at x1 on the object sitting at the
origin. (magnitude and direction. Take the direction from the origin to the right as
POSITIVE)
b) Calculate the gravitational attraction of the object located at X2 on the object at the origin.
(magnitude and direction)
c) Calculate the total gravitational attraction of the objects located at x1 and the object sitting at
x2 on the mass located at the origin. (magnitude and direction).

C

Explanation:

I think its c im pretty sure

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

mass and volume are the answers you are looking for