Help Please:From a height of 45 m, a body of mass 2 kg was allowed to fall freely. Calculate: a) the time of falling of the body b) the speed of the body when hitting the ground c) kinetic energy on impact with the ground; the influence of gravity is g = 10m / s²​

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

It is increased due to the doppler effect. (apex)

+10 that is always the common denominator