Arifle is aimed horizontally at a target 55.0 m away. the bullet hits the target 3.00 cm below the aim point

what was the bullet's flight time?

what was the bullet's speed as it left the barrel?

For the vertical displacement of the bullet,
s = ut + 1/2 at², u = 0 in the vertical direction and a = g
0.03 = 1/2 x 9.81 x t²
t = 0.078 s

The total time of flight is 0.078 seconds

Assuming the bullet travels at a constant horizontal velocity,
distance = velocity x time
v = 55 / 0.078
v = 705.1 m/s

Answerwavelength;