A 0.5 kg bullet is moving at 6000 m/s and it hits a tree. It travels into the tree at a distance of 4 m. What is the strength of the force (work) that stop a bullet?

It's because 3 if it was 10 it wouldn't look right do it goes up to 4d

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

It is 5 hope this you out 

Hellosubatomic particles  are  particles  that are smaller than the atom. protons, neutrons, and electrons are the three mainsubatomic particles  found in an atom. protons have a positive (+)  charge. an easy way to remember this is to remember that both neutron and no  electrical charge  start with the letter "n."have a nice day