At t=0, a stone is dropped from a cliff above a lake; 1.6 s later another stone is thrown downward from the same point with an initial speed of 32 m/s. both stones hit the water at the same instant. find the height of the cliff.

27.52 meters is the height of the cliff.

Explanation:

Second equation of motion:

u = Initial velocity

t = Time taken to cover h  distance

g = Acceleration due to gravity

Let the height of the cliff be h

Stone-1:

Initial velocity of the stone = u = 0 m/s

Time to cover h height of cliff, t = ?, g =

..[1] (Second equation of motion)

Stone-2:

Initial velocity of the stone = u' = 32 m/s,

Time to cover h height of cliff = t' = (t-1.6),

g =

..[2]

Both stones are covering same distance or height of the cliff: [1]= [2]

On solving for t:

t = 2.37 seconds

h = 27.52 m

27.52 meters is the height of the cliff.

the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

the dependent variable, the one that you measure the response in, is the distance that the washers travel.