The volume of an object as a function of time calculated by V=At^3+B/t, where t is time measured in seconds and V is in cubic meters. Determine the dimension of the constants A and B

A = L^3 T^-3  ,  B = L^3 T

Explanation:

Given: volume ( V )  = At^3 + B/t   ( 1 )

dimension of volume = L^3

and the Dimension of time = T

back to equation ( 1 )

L^3 = A * T^3   ( 2 )

also L^3 = B/T ( 3 )

from equation ( 2 )

A = L^3 T^-3

from equation ( 3 )

B = L^3 T

The dimensions of the constants A and B

A = L^3 T^-3  ,  B = L^3 T

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

when cloud cover increases then the suns ray's which provides the earth with light and warmth gets covered due to the due to the suns ray's being blocked, the temperature in that region

therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

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