Physics, 11.04.2021 02:10 animaljamissofab

A car moves in a straight line such that for a short time it's velocity is defined by V = (9t+ 2t) m/s, where t
is in seconds. Determine its position and acceleration when t = 3s.
When t = 0, S=0

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Answer from: bellamuniz2015p23zr7

s = 90 m

a = 56 m/s²

Explanation:

I will ASSUME that your equation is silly as it reduces to V = 11t which is constant, and that you mean V = 9t² + 2t

Position is the integral of differential velocities

s = $\int\limits^3_0 {9t^2 + 2t} \, dt$

s = 3t³ + t² | from 0 to 3

s = 3(3)³ + 3² - (0) = 90 m

acceleration is the derivative of velocity

a = v' = 18t + 2

a(3) = 18(3) + 2 = 56 m/s²

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

I'll do it rn and then answer

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A car moves in a straight line such that for a short time it's velocity is defined by V = (9t+ 2t)...

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