A car starting from rest moves with constant acceleration of 2.0 m/s2 for 10 s, then travels with constant speed lor another 10 s, and then finally slows to a slop will conslanl acceleration of
-2.0 m/s2. How far does it travel?​

d = 400 m

Explanation:

Distance during acceleration

d = ½at² = ½(2.0)10² = 100 m

velocity after 10 s

v = 2.0(10) = 20 m/s

distance at constant speed

d = vt = 20(10) = 200 m

As the acceleration is the same magnitude while slowing down as speeding up, It will take the same distance to complete the deceleration 100 m

Total distance is 100 + 200 + 100 = 400 m

are there answer choices to this question? this seems like a question where you have options to choose from.

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