1) Sodium ions (Na') move at 0.85 m/s through a bloodstream in the arm of a person standing near a large magnet. The magnetic
field has a strength of 0.25 T and makes an angle of 51.0 degrees
with the motion of the sodium ions. Assuming no other ions are
present in the arm, what would be the magnetic force on any of
these ions? (Na has a charge of 1.60 x 10" C)

Answer:   [a]:   "slate" .

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j