How large a force F is needed in the figure to pull out the 6.0 kg block with an acceleration of 1.50 m/s2

if the coefficient of friction at its surfaces is 0.40?​

32.52 N

Explanation:

F-F' = ma Equation 1

Where F = Force needed to pull the block, m = mass of the block, a = acceleration of the block, F' = Frictional force of the surface acting on the blcok

F = ma+F'

But,

F' = μmg

Where g = acceleration due to gravity, μ = coefficient of static friction

F = ma+μmg Equation 2

Given: m = 6.0 kg, a = 1.5 m/s², μ = 0.40

Constant: g = 9.8 m/s²

Substitute these values into equation 2

F = 6(1.5)+6(9.8)(0.4)

F = 9+23.52

F = 32.52 N

yup its correct its: c) b b

this would be about 43%