A cannonball is launched at a 65 degree angle and has a launch velocity of 30 m/s. 1.Calculate the magnitude of the cannonball’s initial vertical velocity

2.Calculate the cannonball’s horizontal range.

3.What other angle could the cannonball be launched at to achieve the same horizontal range. Explain how you know.

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Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !

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