Suppose that you have a certain spring to which you add weights. The spring does not stretch until you add 10 N, but it then stretch 10 cm for every 100 grams that you add. What is the equilibrium weight W0 of this scale, in newtons? The equilibrium weight of this spring is N.

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.