5. A tape attached to an accelerating trolley passes through a ticker that makes dots on it at a frequency of 50Hz The ticker timer makes 10 dots on a 10cm long tape such that, the distance a between the
first two dots is 0.5cm and the distance b between the last two dots is 1 5cm
(a)Determine the velocity of the trolley at:
I Distance a
II Distance b
Determine the acceleration of the trolley.
(6) State with a reason what would be observed on the spacing between the dots on the tape when
the trolley is made to move on a horizontal surface.
al velocity Y in time the distance
illo Y To the​

The answer would be a) -80of

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Wut