A basketball is dropped from top of the rim. It takes 1.3s to fall, what is the displacement? a. 8.45 m
b. 8.321 m
c. 33.67 m
d. 33.8 m

d = 8.45 m

Explanation:

Given that,

A basketball is dropped from top of the rim.

It takes 1.3s to fall.

We need to find the displacement of the basketball. Let the displacement is d. Using second equation of kinematics,

Where

u is the initial velocity, u = 0

a = g

So,

So, the displacement of the basketball is 8.45 m.

. west

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west