1 A 1,500 kg car is at rest on a level track. The driver gives the engine gas and the
car begins to accelerate forward. The car moves from 0 m/s to 27 m/s in 8 sec.
What is the force of the car moving forward? (F = ma)

5625N

Explanation:

first let's get acceleration

a=v-u/t

a=27-0/8

a=27/8

a=3.375 m/s^2

then let's find Force

F=ma

F=1500×3.375

F=5625N

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answer is c

explanation:

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be