By using kirchhoff's laws, it can be shown that the currents i1, i2, and i3 that pass through the three branches of the circuit in the figure satisfy the given linear system. solve the system to find i1, i2, and i3. (round your answers to three decimal places.)

i(sub)1 + i(sub)2 − i3 = 0
8i(sub)1 − 4i(sub)2 = 2
4i(sub)2 + 2i(sub)3 = 8
r = 8, r2 = 4, r3 = 2
v = 2, v(sub)2 = 8