Physics, 28.08.2019 04:40 connorhoran05

Suppose the stone is thrown at an angle of 39.0° below the horizontal from the same building as in the example above. if it strikes the ground 47.8 m away, find the following. (hint: for part (a), use the equation for the x-displacement to eliminate v0t from the equation for the y-displacement.)
(a) the time of flight
s
the x coordinate as a function of time is x(t) = vcos(39.0)t, so the initial speed is v0 = δx/(cos 39.0δt), where δx = 47.8 and δt is the time of flight. insert this into your equation for y(t) and solve for the time of flight.

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Suppose the stone is thrown at an angle of 39.0° below the horizontal from the same building as in t...

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