1. Two point charges, equal amounts of
charge in absolute
value
2,5 C and opposite
in sign, are in the air
at a distance of 10
cm from each other.
How big is it
the intensity of the
electrostatic force
with which these two
point charges act on
each other?
Comment on the
sign of force.

Can someone help me pls​

The answer to this is decibel

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j