PLEASE HELP ME WITH THIS ONE QUESTION The speed of sound at an elevation of 40,000 feet, where many aircraft fly, is 295 m/s. If an airplane is flying at Mach 0.92 at this altitude, how fast is the airplane traveling in meters per second?

The plane travels at a rate of 313 meters per second.

Explanation:

Since the speed of sound at an elevation of 40,000 feet, where many aircraft fly, is 295 m / s, if an airplane is flying at Mach 0.92 at this altitude, to determine how fast is the airplane traveling in meters per second you must perform the following calculation:

1 Mach = 1,225.04 km / h

1 km = 1,000 m

1 h = 3,600 sec

1 = 1225.04

0.92 = X

0.92 x 1225.04 = X

1,127.03 = X

(1,127.03 x 1,000) / 3,600 = X

1,127,030 / 3,600 = X

313.06 = X

Thus, the plane travels at a rate of 313 meters per second.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y