Please help A proton with velocity 7.0 x 10^5m/s collides elastically with a second proton that is stationary. One of the protons moves away at an angle of 45 degrees. Find the angle of the second proton as well as their final velocities after the collision. (Hint: KE = 1/2 mv^2 is not a vettor, Elastic collisions have conservation of momentum and Kinetic energy). Remember this is a system of three equations solve the system. ​

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

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k2s for potassium sulphide

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