I'll mark brainliest Q: You're playing a game of catch with a dog, the dog is initially standing near your feet. Then he jogs 20ft in a straight line to retrieve the stick and carries the stick 15ft back towards you before lying on the ground to chew the stick.
A). Cal the total distance
B) . Total displacement
C). Show that the net displacement of the trip is the sum of the sequential displacement that makes up the trip.​

A) 35 ft

B) 5 ft

C) Net displacement = distance covered by the dog to retrieve the stick - distance covered before the dog starts chewing the stick

Explanation:

A) Total distance covered by the dog = 20 + 15

                                  = 35 ft

B) Since the other distance covered by the dog before chewing the stick, after the retrieval, was in an opposite direction to the initial direction, then;

total displacement of the dog = 20 - 15

                                  = 5 ft

C) Net displacement = distance covered by the dog to retrieve the stick + distance covered before the dog starts chewing the stick

But, displacement involves a specified direction. The distance covered before the dog starts chewing the stick was in an opposite direction to the initial direction.

Thus,

Net displacement = distance covered by the dog to retrieve the stick - distance covered before the dog starts chewing the stick

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