Physics, 28.01.2020 09:31 ellenaschool

Abox is sliding along a frictionless surface and gets to a ramp. disregarding friction, how fast should the box be going on the ground in order to slide up the ramp to a height of 2.5 meters, where it stops? (use g = 9.8 m/s2.)

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Answer from: zayy8595

You have velocity final, distance, acceleration, but you need the velocity initial

vf^2 = vi^2 + 2ad

flip the vf^2 and vi^2 because you're searching for vi

vi=(vf is zero because it comes to a stop) + square root of 2ad

vi= the square root of 2ad
= square root of 2(9.8m/s^2)(2.5m)
vi= 7 m/s

Answer from: Itskiyya

Answer;

7.0 m/s

Solution and explanation;

From the information;

we have the final velocity, distance, and acceleration,

We therefore, need to find initial velocity;

Using the equation;

vf^2 = vi^2 + 2ad

Making, vi² the subject;

vi² = vf² - 2ad

but; vf is zero because it comes to a stop or rest

Thus; vi² = - 2ad

vI = √(2ad)

vi= the square root of 2ad

= √(2×9.8 × 2.5)

vi= 7 m/s

Therefore; initial velocity = 7 m/s

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

Answershe should not have multiplied the sulfur atoms by the subscript 4

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Abox is sliding along a frictionless surface and gets to a ramp. disregarding friction, how fast sho...

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