The charges of two particles are as follows: Q1=2 x 10 -8 C and Q2 = 3 x 10 -7 C. Find the magnitude of the force between these charges if Q1 is located at (2, 5, 1) and Q2 is located at (3, 2, 3).

F = 3.86 x 10⁻⁶ N

Explanation:

First, we will find the distance between the two particles:

where,

r = distance between the particles = ?

(x₁, y₁, z₁) = (2, 5, 1)

(x₂, y₂, z₂) = (3, 2, 3)

Therefore,

Now, we will calculate the magnitude of the force between the charges by using Coulomb's Law:

where,

F = magnitude of force = ?

k = Coulomb's Constant = 9 x 10⁹ Nm²/C²

q₁ = magnitude of first charge = 2 x 10⁻⁸ C

q₂ = magnitude of second charge = 3 x 10⁻⁷ C

r = distance between the charges = 3.741 m

Therefore,

F = 3.86 x 10⁻⁶ N

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