Engineers are usi g computer models to study train collisions to design safer train cars. They start by modeling an elastic collision between 2 train cars traveling towards each other. Car 1 is traveling east at 6 m/s and has a mass of 3, 154kg. Car 2 is traveling west at 23 m/s and has a mass of 8,296kg. After the collision car 1 has a final velocity of 7 m/s west. What is the final velocity of car 2?

Why does the input force have to be greater than the force needed to lift the bale?

1.)the isotope cobalt-60 has a nuclear mass of 59.933820 u calculate the mass defect of cobalt-60 using the following information. mass of proton: 1.007825 u mass of neutron: 1.008665 u 1 u = 931.5 mev 2.)the isotope cobalt-60 has a nuclear mass of 59.933820 u calculate the binding energy of cobalt-60 using the following information. mass of proton: 1.007825 u mass of neutron: 1.008665 u 1 u = 931.5 mev 3.)the isotope cobalt-60 has a nuclear mass of 59.933820 u calculate the binding energy per nucleon of cobalt-60 using the following information. mass of proton: 1.007825 u mass of neutron: 1.008665 u 1 u = 931.5 mev

Consider two less-than-desirable options. in the first you are driving 30 mph and crash head-on into an identical car also going 30 mph. in the second option you are driving 30 mph and crash head-on into a stationary brick wall. in neither case does your car bounce off the thing it hits, and the collision time is the same in both cases. which of these two situations would result in the greatest impact force?