A weightlifter lifts a set of weights a vertical distance of 2.0 m. If a constant net force of 350 N is exerted on the weights, what is the net work done on the weights?

700 Joules

Explanation:

The work done equals force times distance. Just multiply your two values there.

Side note: It would be more impressive if he'd done it in 1 second rather than 5. You know why? Because POWER=WORK/TIME. The less time it takes him to lift the weight with the same force and distance, the more powerful he is!

anchor = archer //

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach