The recoil of a cannon is probably familiar to anyone who has watched pirate movies. This is a classic problem in momentum conservation. Consider a wheeled, 500 kg cannon firing a 2 kg cannonball horizontally from a ship. The ball leaves the cannon traveling at 200 m/s. At what speed does the cannon recoil as a result?

0.8 m/s

Explanation:

From the question,

MV = mv Equation 1

Where M = mass of the cannon, m = mass of the cannonball, V = velocity of the cannon, v = velocity of the cannon ball.

make V the subject of the equation

V = mv/M Equation 2

Given: m = 2 kg, M = 500 kg, v = 200 m/s

Substitute these value into equation 2

V = (2×200)/500

V = 400/500

V = 0.8 m/s

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

32: from largest to smallest, this hierarchy includes eons, eras, periods, epochs, and ages.

33: answer is c

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