A car of weight 11 000 N moves with constant velocity along a horizontal road. A driving force of 5000 N acts on the car. What is the force opposing the motion of the car?

f = 5000 N

Explanation:

Given that,

The weight of a car = 11000 N

Driving force on the car = 5000 N

We need to find the force opposing the motion of the car. The net force on th car is given by :

F-f = ma

As it moves with constant velocity, a = 0

i.e.

F - f = 0

F = f

f = 5000 N

Hence, the opposing force is 5000 N.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force