Three vector are oriented as shown in figure below where. A=20.0units, B=40.0units, And C=30.0. (a) The x and Y component of the resultant vector. (b) The magnitude of the resultant vector. (c) Direction of the resultant vector ​ { please help me}

Explanation:

a). Vertical component of vector B = Bsin(45)

                                                     = 40sin(45°)

                                                     = 28.28 units

Horizontal component of vector B = Bcos(45°)

                                                         = 40cos(45°)

                                                         = 28.28 units

Vertical component of vector C = Csin(45°)

                                                     = 30sin(45°)

                                                     = 21.21 units

Horizontal component of vector C = Ccos(45°)

                                                         = 30cos(45°)

                                                         = 21.21 units

Vertical forces = A + Bsin(45°) - Csin(45°)

                       = 20 + 28.28 - 21.21

                       = 27.07

Horizontal forces = Bcos(45°) + Ccos(45°)

                             = 28.28 + 21.21

                             = 49.49 units

b). Magnitude of resultant force =

                                                =

                                                = 56.41 units

c). Direction of the resultant force → Along vector B (at an angle of 45° from the horizontal line)

an energy transformation flow diagram is shown

where is it ?

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete