A child falls sideways off the sled while sledding on frictionless ice. What happens to the velocity of the sled

Same as before.

Explanation:

we can use momentum conservation to solve the problem.

Let mass of child be m and of the sled be M. Also let both have initial velocity u.

since, child fells off on the sled it will still have same velocity of ''u''.

By momentum conservation we have,

(M + m) x u = m x u + M x v

⇒ Mu=Mv

⇒ u=v

Hence, velocity of the sled remains the same.

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.