Determine the diameter of wire with a circular cross-section that has tensile force of 60.0Newtons, and this force produces a stress of 3 060 000 pascal ​

the diameter of the wire is 5 mm.

Explanation:

Given;

tensile force of the wire, F = 60 N

stress on the wire, δ = 3,060,000 Pa = 3,060,000 N/m²

Let A be the cross sectional area of the wire

The cross sectional area of the wire is calculated as follows;

The diameter of the wire is calculated as follows;

Therefore, the diameter of the wire is 5 mm.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

+15-35=-20

going in opposite directions