Dos cargas puntuales se localizan en el eje +X de un sistema de coordenadas. La carga q1= 1nC esta a 2cm del origen y la carga q2= -3 nC esta a 4cm del origen. ¿cual es la fuerza tras que ejercen estas dos cargas sobre una carga q3= 5nC que se encuentra en el origen?

F_net = 1.125 10⁻⁶ N

positive direction of the x axis

Explanation:

The electric force is given by Coulomb's law

           F =

also used  charge of equal sign repel each other.

We appease this information to our problems

the charge q₁ is positive and the charge q₃ is positive for which the force is repulsive; ; a charge q₂ is negative so the force is attractive.

If we apply that the forces are vectors

            F_net = - F₁₃ + F₂₃

           F_net =

            F_net = k q₃ ( )

let's look for the distances

          r₁₃ = 2-0 = 2 cm = 2 10⁻² m

          r₂₃ = 4-0 = 4 cm = 4 10⁻² m

let's substitute

            F_net = 9 10⁹ 5 10⁻⁹ ( )

            F_net = 45 (- 0.5 10⁻⁷ + 0.75 10⁻⁷)

            F_net = 1.125 10⁻⁶ N

the positive sign indicates that the outside has a positive direction of the x axis, that is, it is to the right

explanation: in any substance/object, the particles inside it (atoms/molecules) constantly move in random directions and with random speeds (this motion is called brownian motion). as a result, the particles have some kinetic energy (which is proportional to the temperature of the substance).

explanation:

have a great day!

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.