Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign. Find the currents flowing in the circuit in the figure below. (Assume the resistances are
R1 = 10 Ω,

R2 = 6 Ω,

R3 = 8 Ω,

R4 = 15 Ω,

r1 = 0.75 Ω,

r2 = 0.5 Ω,

r3 = 0.75 Ω,
and
r4 = 0.25 Ω.)
Find I1, 2, and 3.

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y