How much power is required to carry a 35N package a vertical distance of 18 m if the work on
the package is accomplished in 30 s?

Explanation:

force=35

distance=18

time=30

power=f×d/t

p=35×18/30

p=21

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west