La figura muestra dos partículas con carga positiva fijas sobre un lugar sobre el eje x. Las cargas son q1=1.60E-19 C y q2=3.2E-19 C. La separación es de r=0.020 m. ¿Cuál es la magnitud y dirección de la fuerza eléctrica que ejerce la carga q2 sobre la carga q1?

Distance^2= yellow line ^2 (see picture) = 30^2 + 49^2so distance = squareroot of (300^2 +49^2)i dont know if this is how to solve it, but i cnt think of another way

The answer is water molecules are split.cellular respiration and photosynthesis are complement  reactions to each other. these are reverse reactions. in cellular respiration glucose and oxygen yield water and carbon dioxide. so, when respiration begins,  glucose molecules are split. in the opposite reaction - in photosynthesis, carbon dioxide and water yield glucose and oxygen. thus,  when respiration begins, water molecules are split.

Ithink it’s: light bounce if off a mirror