To what temperature will a 50.0 g piece of glass raise if it absorbs 5275 joules of heat and its specific heat capacity is 0.50 J/g°C? The initial temperature of the glass is 20.0°C.

Final temperature, T2 = 131895°C

Explanation:

Given the following data;

Mass = 50g

Initial temperature = 20°C

Quantity of heat = 5275J

Specific heat capacity = 0.50 J/g°C

To find the final temperature;

Heat capacity is given by the formula;

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Making dt the subject of formula, we have;

Substituting into the equation, we have;

dt = 131875°C

Now, the final temperature T2 is;

But, dt = T2 - T1

T2 = dt + T1

T2 = 131875 + 20

T2 = 131895°C

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