Hola! Necesito ayuda con una tarea de Física, prontom es para el miercoles 3/3/2021, son varias preguntas, pero con contestar al menos una me ayudan mucho: 1) En cuanto tiempo un móvil que ha partido del reposo adquiere una rapidez de 20m/s, sabiendo que su aceleración es de 50m/s^2.

2) Calcular la rapidez con la cual se desplazaba un móvil que al cabo de 0,5 min de estarse moviendo con una aceleración de 0,5m/s^2 tiene una rapidez de 54km/h.

3) Un móvil parte con una velocidad de 18km/h al cabo de 1,5 min, tiene una rapidez (O velocidad) de 342km/h. Calcular la distancia que recorre en ese lapso de tiempo.

Se los agradezco mucho a todos por su gran ayuda, me estarian salvando la materia, ya que con la cuarentena solo he tenido dos actividades de Física, gracias nuevamente.

answer is c

explanation:

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.