a proton of charge +e and mass 1.67×10^-27kg is shot with a speed 2.0×10^5. what will be it's speed just before hitting the plate at P​

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

it is called kinetic energy

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

c) up

hope this