A33 kg gun is standing on a frictionless surface. the gun fires a 57.7g bullet with a muzzle velocity of 325m/s. the positive direction is that of the bullet.
calculate the kinetic energy of thebullet immediately after the gun was fired. answer in units of j

Kinetic Energy =  (1/2) mv^2.

m = 57.7 g = 57.7/1000 = 0.00577 kg.
v = 325 m/s.

E = 0.5 * 0.00577 * 325^ 2.    Use your calculator.

E = 304.728125  J.

That's the kinetic energy.

British cologoinst admisitrion

Make them both to where they have the denominator of 18that makes 3/2 equal 27/18 and 1/9 equal 2/18so now you have  27/18x+5=2/18subtract 5 from the other sideso now you have 27/18x+2/18-5then subtract 2/18 from 27/18 to get 25/18x=-5then divide 25/18 by -5 and your answer will be  -5/18